[Syrupmakers] Chains and sprockets

Charles Deese cdeese at hotmail.com
Tue Feb 19 17:36:07 PST 2008


You need to divide by the radius in feet, ie 3" = 0.25ft.  2500ft lb of torque on the mill shaft with a 6" dia. sprocket would be 2500 ft lb divided by 0.25 ft = 10,000 lbs of force on the chain.

Charles
----------------------------------------
> Date: Tue, 19 Feb 2008 16:56:54 -0800
> From: rattrapsc at yahoo.com
> Subject: Re: [Syrupmakers] Chains and sprockets
> To: syrupmakers at syrupmakers.net
> 
> JT,
> The strengths of std. single roller chain is as
> follows.(according to GRAINGER) #60 1980lb max.
> working and 9920lb breaking. #80 3300lb max. working
> and 17,640lb breaking. #100 5070lb max. working and
> 26,460lb breaking. If you divide the max. ft lbs of
> torque expected by the radius of your final drive
> sprocket, that should be the lbs being applied to your
> chain.  example : 2500ft lb of torque on mill shaft
> with 6" dia. sprocket is 3" rad. 2500 divided by
> 3=833lb on chain. I'm pretty shure that is correct.
> I'm no engineer. If I told you wrong, perhaps someone
> else will reply.
> Jay
> --- DBACrownhoney at aol.com wrote:
> 
>> I was wondering if ya'll had an opinion on chain and
>> sprocket sizes for  
>> converting a Chattanooga 13 to engine powered. The
>> southernmatters web site says  
>> to use a 100 size chains, but I went to a industrial
>> supply store to look  at 
>> some and they are huge. It just seems like overkill.
>>  
>>  
>>  
>> JT
>> 
>> 
>> 
>> **************Ideas to please picky eaters. Watch
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>>
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>> 
> 
> 
> Jay
> 
> 
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